Wednesday, March 28, 2012

Parameter multi-value problem when using a stored procedure

Hi folks,
I am describing the issue as below:
1. create a stored procedure as below
....where age in (@.p_age)
note: age is the table coumn of table table1 with datatype tinyint
2. .... and create a second dataset for parameter @.p_age
select distinct age from table1
3. associate the parameter...run it
4. There is no problem with single value. But when two ages are selected,
I got error message, "...Erro convert data type nvarchar to tinyint"
Please advise. PeterYou cannot pass and use multi-value parameters to a stored procedure and use
it in a query as you have. If that query was in RS itself then it would
work. This is not a RS thing, it is a SQL Server stored procedure issue.
Just try it from Query Analyzer and you will see what I mean. I do the
following, I create
"Peter" <Peter@.discussions.microsoft.com> wrote in message
news:74D9A9F0-B1F9-4925-8080-87FC99215462@.microsoft.com...
> Hi folks,
> I am describing the issue as below:
> 1. create a stored procedure as below
> ....where age in (@.p_age)
> note: age is the table coumn of table table1 with datatype tinyint
> 2. .... and create a second dataset for parameter @.p_age
> select distinct age from table1
> 3. associate the parameter...run it
> 4. There is no problem with single value. But when two ages are selected,
> I got error message, "...Erro convert data type nvarchar to tinyint"
> Please advise. Peter|||Try again, sent before done:
What doesn't work has nothing really to do with RS but has to do with Stored
Procedures in SQL Server. You cannot do the following in a stored procedure.
Let's say you have a Parameter called @.MyParams
Now you can map that parameter to a multi-value parameter but if in your
stored procedure you try to do this:
select * from sometable where somefield in (@.MyParams)
It won't work. Try it. Create a stored procedure and try to pass a
multi-value parameter to the stored procedure. It won't work.
What you can do is to have a string parameter that is passed as a multivalue
parameter and then change the string into a table.
This technique was told to me by SQL Server MVP, Erland Sommarskog
For example I have done this
inner join charlist_to_table(@.STO,Default)f on b.sto = f.str
So note this is NOT an issue with RS, it is strictly a stored procedure
issue.
Here is the function:
CREATE FUNCTION charlist_to_table
(@.list ntext,
@.delimiter nchar(1) = N',')
RETURNS @.tbl TABLE (listpos int IDENTITY(1, 1) NOT NULL,
str varchar(4000),
nstr nvarchar(2000)) AS
BEGIN
DECLARE @.pos int,
@.textpos int,
@.chunklen smallint,
@.tmpstr nvarchar(4000),
@.leftover nvarchar(4000),
@.tmpval nvarchar(4000)
SET @.textpos = 1
SET @.leftover = ''
WHILE @.textpos <= datalength(@.list) / 2
BEGIN
SET @.chunklen = 4000 - datalength(@.leftover) / 2
SET @.tmpstr = @.leftover + substring(@.list, @.textpos, @.chunklen)
SET @.textpos = @.textpos + @.chunklen
SET @.pos = charindex(@.delimiter, @.tmpstr)
WHILE @.pos > 0
BEGIN
SET @.tmpval = ltrim(rtrim(left(@.tmpstr, @.pos - 1)))
INSERT @.tbl (str, nstr) VALUES(@.tmpval, @.tmpval)
SET @.tmpstr = substring(@.tmpstr, @.pos + 1, len(@.tmpstr))
SET @.pos = charindex(@.delimiter, @.tmpstr)
END
SET @.leftover = @.tmpstr
END
INSERT @.tbl(str, nstr) VALUES (ltrim(rtrim(@.leftover)),
ltrim(rtrim(@.leftover)))
RETURN
END
GO
Bruce Loehle-Conger
MVP SQL Server Reporting Services
"Peter" <Peter@.discussions.microsoft.com> wrote in message
news:74D9A9F0-B1F9-4925-8080-87FC99215462@.microsoft.com...
> Hi folks,
> I am describing the issue as below:
> 1. create a stored procedure as below
> ....where age in (@.p_age)
> note: age is the table coumn of table table1 with datatype tinyint
> 2. .... and create a second dataset for parameter @.p_age
> select distinct age from table1
> 3. associate the parameter...run it
> 4. There is no problem with single value. But when two ages are selected,
> I got error message, "...Erro convert data type nvarchar to tinyint"
> Please advise. Peter

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